\(\int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx\) [319]

Optimal result

Integrand size = 26, antiderivative size = 117 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx=-\frac {16 i (a+i a \tan (c+d x))^{15/2}}{15 a^4 d}+\frac {24 i (a+i a \tan (c+d x))^{17/2}}{17 a^5 d}-\frac {12 i (a+i a \tan (c+d x))^{19/2}}{19 a^6 d}+\frac {2 i (a+i a \tan (c+d x))^{21/2}}{21 a^7 d} \]

[Out]

-16/15*I*(a+I*a*tan(d*x+c))^(15/2)/a^4/d+24/17*I*(a+I*a*tan(d*x+c))^(17/2)/a^5/d-12/19*I*(a+I*a*tan(d*x+c))^(1
9/2)/a^6/d+2/21*I*(a+I*a*tan(d*x+c))^(21/2)/a^7/d

Rubi [A] (verified)

Time = 0.11 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {3568, 45} \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx=\frac {2 i (a+i a \tan (c+d x))^{21/2}}{21 a^7 d}-\frac {12 i (a+i a \tan (c+d x))^{19/2}}{19 a^6 d}+\frac {24 i (a+i a \tan (c+d x))^{17/2}}{17 a^5 d}-\frac {16 i (a+i a \tan (c+d x))^{15/2}}{15 a^4 d} \]

[In]

Int[Sec[c + d*x]^8*(a + I*a*Tan[c + d*x])^(7/2),x]

[Out]

(((-16*I)/15)*(a + I*a*Tan[c + d*x])^(15/2))/(a^4*d) + (((24*I)/17)*(a + I*a*Tan[c + d*x])^(17/2))/(a^5*d) - (
((12*I)/19)*(a + I*a*Tan[c + d*x])^(19/2))/(a^6*d) + (((2*I)/21)*(a + I*a*Tan[c + d*x])^(21/2))/(a^7*d)

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 3568

Int[sec[(e_.) + (f_.)*(x_)]^(m_)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[1/(a^(m - 2)*b
*f), Subst[Int[(a - x)^(m/2 - 1)*(a + x)^(n + m/2 - 1), x], x, b*Tan[e + f*x]], x] /; FreeQ[{a, b, e, f, n}, x
] && EqQ[a^2 + b^2, 0] && IntegerQ[m/2]

Rubi steps \begin{align*} \text {integral}& = -\frac {i \text {Subst}\left (\int (a-x)^3 (a+x)^{13/2} \, dx,x,i a \tan (c+d x)\right )}{a^7 d} \\ & = -\frac {i \text {Subst}\left (\int \left (8 a^3 (a+x)^{13/2}-12 a^2 (a+x)^{15/2}+6 a (a+x)^{17/2}-(a+x)^{19/2}\right ) \, dx,x,i a \tan (c+d x)\right )}{a^7 d} \\ & = -\frac {16 i (a+i a \tan (c+d x))^{15/2}}{15 a^4 d}+\frac {24 i (a+i a \tan (c+d x))^{17/2}}{17 a^5 d}-\frac {12 i (a+i a \tan (c+d x))^{19/2}}{19 a^6 d}+\frac {2 i (a+i a \tan (c+d x))^{21/2}}{21 a^7 d} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.47 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.62 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx=\frac {2 a^3 (-i+\tan (c+d x))^7 \sqrt {a+i a \tan (c+d x)} \left (-3243+7365 i \tan (c+d x)+5865 \tan ^2(c+d x)-1615 i \tan ^3(c+d x)\right )}{33915 d} \]

[In]

Integrate[Sec[c + d*x]^8*(a + I*a*Tan[c + d*x])^(7/2),x]

[Out]

(2*a^3*(-I + Tan[c + d*x])^7*Sqrt[a + I*a*Tan[c + d*x]]*(-3243 + (7365*I)*Tan[c + d*x] + 5865*Tan[c + d*x]^2 -
(1615*I)*Tan[c + d*x]^3))/(33915*d)

Maple [A] (verified)

Time = 0.61 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.70

\[\frac {2 i \left (\frac {\left (a +i a \tan \left (d x +c \right )\right )^{\frac {21}{2}}}{21}-\frac {6 a \left (a +i a \tan \left (d x +c \right )\right )^{\frac {19}{2}}}{19}+\frac {12 a^{2} \left (a +i a \tan \left (d x +c \right )\right )^{\frac {17}{2}}}{17}-\frac {8 a^{3} \left (a +i a \tan \left (d x +c \right )\right )^{\frac {15}{2}}}{15}\right )}{d \,a^{7}}\]

[In]

int(sec(d*x+c)^8*(a+I*a*tan(d*x+c))^(7/2),x)

[Out]

2*I/d/a^7*(1/21*(a+I*a*tan(d*x+c))^(21/2)-6/19*a*(a+I*a*tan(d*x+c))^(19/2)+12/17*a^2*(a+I*a*tan(d*x+c))^(17/2)
-8/15*a^3*(a+I*a*tan(d*x+c))^(15/2))

Fricas [B] (verification not implemented)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 202 vs. \(2 (85) = 170\).

Time = 0.30 (sec) , antiderivative size = 202, normalized size of antiderivative = 1.73 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx=-\frac {2048 \, \sqrt {2} {\left (16 i \, a^{3} e^{\left (21 i \, d x + 21 i \, c\right )} + 168 i \, a^{3} e^{\left (19 i \, d x + 19 i \, c\right )} + 798 i \, a^{3} e^{\left (17 i \, d x + 17 i \, c\right )} + 2261 i \, a^{3} e^{\left (15 i \, d x + 15 i \, c\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}}{33915 \, {\left (d e^{\left (20 i \, d x + 20 i \, c\right )} + 10 \, d e^{\left (18 i \, d x + 18 i \, c\right )} + 45 \, d e^{\left (16 i \, d x + 16 i \, c\right )} + 120 \, d e^{\left (14 i \, d x + 14 i \, c\right )} + 210 \, d e^{\left (12 i \, d x + 12 i \, c\right )} + 252 \, d e^{\left (10 i \, d x + 10 i \, c\right )} + 210 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 120 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 45 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 10 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]

[In]

integrate(sec(d*x+c)^8*(a+I*a*tan(d*x+c))^(7/2),x, algorithm="fricas")

[Out]

-2048/33915*sqrt(2)*(16*I*a^3*e^(21*I*d*x + 21*I*c) + 168*I*a^3*e^(19*I*d*x + 19*I*c) + 798*I*a^3*e^(17*I*d*x
+ 17*I*c) + 2261*I*a^3*e^(15*I*d*x + 15*I*c))*sqrt(a/(e^(2*I*d*x + 2*I*c) + 1))/(d*e^(20*I*d*x + 20*I*c) + 10*
d*e^(18*I*d*x + 18*I*c) + 45*d*e^(16*I*d*x + 16*I*c) + 120*d*e^(14*I*d*x + 14*I*c) + 210*d*e^(12*I*d*x + 12*I*
c) + 252*d*e^(10*I*d*x + 10*I*c) + 210*d*e^(8*I*d*x + 8*I*c) + 120*d*e^(6*I*d*x + 6*I*c) + 45*d*e^(4*I*d*x + 4
*I*c) + 10*d*e^(2*I*d*x + 2*I*c) + d)

Sympy [F(-1)]

Timed out. \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx=\text {Timed out} \]

[In]

integrate(sec(d*x+c)**8*(a+I*a*tan(d*x+c))**(7/2),x)

[Out]

Timed out

Maxima [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.65 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx=\frac {2 i \, {\left (1615 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {21}{2}} - 10710 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {19}{2}} a + 23940 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {17}{2}} a^{2} - 18088 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {15}{2}} a^{3}\right )}}{33915 \, a^{7} d} \]

[In]

integrate(sec(d*x+c)^8*(a+I*a*tan(d*x+c))^(7/2),x, algorithm="maxima")

[Out]

2/33915*I*(1615*(I*a*tan(d*x + c) + a)^(21/2) - 10710*(I*a*tan(d*x + c) + a)^(19/2)*a + 23940*(I*a*tan(d*x + c
) + a)^(17/2)*a^2 - 18088*(I*a*tan(d*x + c) + a)^(15/2)*a^3)/(a^7*d)

Giac [F]

\[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx=\int { {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {7}{2}} \sec \left (d x + c\right )^{8} \,d x } \]

[In]

integrate(sec(d*x+c)^8*(a+I*a*tan(d*x+c))^(7/2),x, algorithm="giac")

[Out]

integrate((I*a*tan(d*x + c) + a)^(7/2)*sec(d*x + c)^8, x)

Mupad [B] (verification not implemented)

Time = 16.01 (sec) , antiderivative size = 690, normalized size of antiderivative = 5.90 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx=\text {Too large to display} \]

[In]

int((a + a*tan(c + d*x)*1i)^(7/2)/cos(c + d*x)^8,x)

[Out]

(a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i + d*x*2i) + 1))^(1/2)*247808i)/(969*d*(exp(c*2i + d*x*
2i) + 1)^4) - (a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i + d*x*2i) + 1))^(1/2)*16384i)/(33915*d*(
exp(c*2i + d*x*2i) + 1)) - (a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i + d*x*2i) + 1))^(1/2)*4096i
)/(11305*d*(exp(c*2i + d*x*2i) + 1)^2) - (a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i + d*x*2i) + 1
))^(1/2)*2048i)/(6783*d*(exp(c*2i + d*x*2i) + 1)^3) - (a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i
+ d*x*2i) + 1))^(1/2)*32768i)/(33915*d) - (a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i + d*x*2i) +
1))^(1/2)*1943552i)/(1615*d*(exp(c*2i + d*x*2i) + 1)^5) + (a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c
*2i + d*x*2i) + 1))^(1/2)*12019712i)/(4845*d*(exp(c*2i + d*x*2i) + 1)^6) - (a^3*(a - (a*(exp(c*2i + d*x*2i)*1i
- 1i)*1i)/(exp(c*2i + d*x*2i) + 1))^(1/2)*95516672i)/(33915*d*(exp(c*2i + d*x*2i) + 1)^7) + (a^3*(a - (a*(exp
(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i + d*x*2i) + 1))^(1/2)*4159488i)/(2261*d*(exp(c*2i + d*x*2i) + 1)^8) - (
a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i + d*x*2i) + 1))^(1/2)*260096i)/(399*d*(exp(c*2i + d*x*2
i) + 1)^9) + (a^3*(a - (a*(exp(c*2i + d*x*2i)*1i - 1i)*1i)/(exp(c*2i + d*x*2i) + 1))^(1/2)*2048i)/(21*d*(exp(c
*2i + d*x*2i) + 1)^10)